Recuerda esto en el futuro.

Hi current Jesús, i'm writing from the future. Now you think that you are clear about C, pointer, strings, etc. But i know you so well, and i know that in the future, you'll need this code to open your mind and remember what you knew in the past about pointers.

For example, when you want to declare a string in C, i usually do:

char* foo = "myString";

or i can do:

char foo[] = "myString";

Ok, but, what about lists of strings? I mean, if i want to declare a list of strings, i could do this:

char* foo[] = {"myString1", "myString2"};


But now i was in the tube coming back to home and i was thinking about how to do this with pointers (i know that it is simply but i'm excited because i'm learning C and i discover that my thoughts weren't so far from reality)

So, this is another way to do the same, but knowledge is free :)

char** foo = (char**) malloc(sizeof(char*)*numberOfStrings);
foo[0] = "myString1";
foo[1] = "myString2";

Thanks Jesús from the future!!!!!!! :D